
Lesson 33: Differential Equations
The examples in this lesson show you how to solve an initial-value
prolilem for a first-order differential equation and how to plot a phase
plane solution of a differential equation.
Example: Find y{t) for t = 8 where Y'{T) = - 2Y~ and
y(0) = 0. Find the answer to within an error tolerance of
KFE
Step 1: Select e d i
(ENTER)
in the SOLVE application.
Ш
F:
INDEP: X INIT: 0 FINflL:6.5
SDLN: Y INIT: 0 FINHL:
TDL:.0001 STEP: Df It _ STIFF
EHTEF; FUNCTION OF INDEP flND SPIN
Step 2: Enter the right hand expression (^ 2V'-) into F'. Notice
that the variables appear in the menu as soon as you begin
the command line, so that you can use them as typing aids.
CD 1 © ai i SD © T [V
2 ® 0 2 ® Y (zD 2
(ENTER) (3 T (ENTER)
p: ' 1/(1+T2^'-2*Y'''2'
INDEP: T INIT: Is—FINF|L:F.. S
SDLN: V INIT: 0 FINAL:
TDL:.0001 STEP: Df It _ STIFF
ENTER INITIAL INDEP VAR VALUE
BiilTMMBBiMMMIIilll li) III I |l|l| I
Step 3: Check the remaining fields. You are using the default values
for the solution (Y) variable name as well as for the initial
values (0 and 0). You can use the default value for
(the iterative step size) as well. Change the final value for
to 8, and the tolerance to 1E--7.
(© 8 (ENTER)
(T] 1 (EEX I 7 (V-1 (ENTER)
p: '1 .■■■■ < 1 +T''-2 ) -2*Y-''2'
INDEP: X INIT: 0 FINAL: 8
SDLN: Y INIT: 0 FINAL:
TDL:.000,„ STEP: 1^03 _STIFF
ENTER INITIAL STEP SIZE
1МШ1 тжюзт
Calculus, Statistics and Advanced Mathematics 7-11
Komentarze do niniejszej Instrukcji